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山西省2023~2024学年度第一学期高三期中质量检测(243220Z)数学.考卷答案试卷答案
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HD4.①g8973%☐111：42weremorelikelytoratetherobot'sactionsasintentional,ratherthanprogrammed,whilethosewhoonlyinteractedwiththemachine-likerobotwerenot.Thisshowsthatmereexposuretoahuman-likerobotisnotenoughtomakepeoplebelieveitiscapableofthoughtsandemotions.Itishuman-likebehaviorthatmightbecrucialforbeingdeemedasanintentionalagent.AccordingtoWykowska,thesefindingsshowthatpeoplemightbemorelikelytobelieveartificialintelligenceiscapableofindependentthoughtwhenitcreatestheimpressionthatitcanbehavejustlikehumans."Thiscouldinformthedesignofsocialrobotsofthefuture,"shesaid.【高三英语第5页（共10页）】·23-112C·28.Whatwereparticipantsaskedtodointheexperiment?A.Behavelikearobot.B.Completeaquestionnaire.C.Showpicturesoftherobot.D.WatchthebehavioroftheiCub.29.Whatdoestheunderlinedword"deemed"inparagraph4probablymean?A.Performed.B.Persuaded.C.Believed.D.Advocated.30.Whatcouldthefindingsbeappliedto?A.Addressingsometechniqueproblems.B.Creatingsocialrobotsjustlikehumans.C.Developingartificialintelligenceindustry.D.Guidingthedesignoffuturesocialrobots.31.Whatwouldbeasuitabletitleforthetext?A.Human-likerobotscaninteractwithhumansB.Human-likerobotscanbehavejustlikehumansC.Human-likerobotsmaybethoughttohavementalstatesD.ArtificialintelligencehasbecomepartofoureverydaylifeDAmethodtotransformacommonlythrown-awayplastictoaresin(usedin3Dprintingcouldallowformakingbetteruseofplasticwaste.AteamofWashingtonStateUni-versityresearchersdevelopedasimpleandefficientwaytotransformpolylacticacid(PLA)(聚乳酸)，abio-basedplasticusedinproductssuchasfilament,plasticsilverwareandfoodpackagingtoahigh-qualityresin."Wefoundawaytoimmediatelyturnthisintosomethingthat'sstrongerandbetter,andwehopethatwillprovidepeoplewiththeinspirationtoupcyclethisstuffinsteadofjustthro-wingitaway,"saidYu-ChungChang,apostdoctoralresearcherintheWSUSchoolofMe-chanicalandMaterialsEngineeringandaco-correspondingauthoronthework."Wemadestrongermaterialsjuststraightoutoftrash.Webelievethiscouldbeagreatopportunity.Althoughit'sbio-based,PLA,whichiscategorizedasanumber7plasticitcanfloatinfreshorsaltwaterforayearwithoutbreakingdown.Itisalsorarelyrecycledbecauselikemanyplastics,whenit'smelteddownandre-formed,itdoesn'tperformaswellastheoriginalversionandbecomeslessvaluable."It'sbiodegradableandcompostable,butonceyoulookintoit,itturnsoutthatitcantakeupto100yearsforittorotawayinalandfill,"Changsaid."Inreality,itstillcreatesalotofpollution.WewanttomakesurethatwhenwedostartproducingPLAonthemillion-tonsscale,wewillknowhowtodealwithit.WhiletheresearchersfocusedonPLAforthestudy,theyhopetoapplytheworktopolyethyleneterephthalate(PET)(涤纶树脂)，whichismorecommonthanPLAandhasasimilarchemicalstructureandpresentsabiggerwasteproblem.Theyhavefiledatemporarypatent【高三英语第6页（共10页）】·23-112C·
分析（I）曲线C1：$\left\{\begin{array}{l}{x=tcosα}\\{y=tsinα}\end{array}\right.$（t为参数，t≠0），其中0≤α＜π，相除法即可得出直角坐标方程．曲线C2：ρ=2sinθ，化为ρ2=2ρsinθ，利用$\left\{\begin{array}{l}{x=ρcosθ}\\{y=ρsinθ}\end{array}\right.$即可化为直角标准方程：x2+y2=2y，联立即可解出．
（II）曲线C3：ρ=2$\sqrt{3}$cosθ．化为ρ2=2$\sqrt{3}$ρcosθ，利用$\left\{\begin{array}{l}{x=ρcosθ}\\{y=ρsinθ}\end{array}\right.$，即可化为直角标准方程：x2+y2=2$\sqrt{3}$x，联立即可解出．利用两点之间的距离公式与三角函数的单调性即可得出|AB|的最大值是4．
解答解：（I）曲线C1：$\left\{\begin{array}{l}{x=tcosα}\\{y=tsinα}\end{array}\right.$（t为参数，t≠0），其中0≤α＜π，化为直角坐标方程：y=xtanα，0≤α＜π，
曲线C2：ρ=2sinθ，化为ρ2=2ρsinθ，化为直角标准方程：x2+y2=2y，联立$\left\{\begin{array}{l}{y=xtanα}\\{{x}^{2}+{y}^{2}=2y}\end{array}\right.$，化为（1+tan2α）x2-2xtanα=0，解得$\left\{\begin{array}{l}{x=0}\\{y=0}\end{array}\right.$，$\left\{\begin{array}{l}{x=sin2α}\\{y=2si{n}^{2}α}\end{array}\right.$．
∴交点直角坐标（0，0），（sin2α，2sin2α）．
（II）曲线C3：ρ=2$\sqrt{3}$cosθ．化为ρ2=2$\sqrt{3}$ρcosθ，化为直角标准方程：x2+y2=2$\sqrt{3}$x，联立$\left\{\begin{array}{l}{y=xtanα}\\{{x}^{2}+{y}^{2}=2\sqrt{3}x}\end{array}\right.$，
化为（1+tan2α）x2-2$\sqrt{3}$x=0，解得$\left\{\begin{array}{l}{x=0}\\{y=0}\end{array}\right.$，$\left\{\begin{array}{l}{x=2\sqrt{3}co{s}^{2}α}\\{y=\sqrt{3}sin2α}\end{array}\right.$．
∴交点直角坐标（0，0），（$2\sqrt{3}co{s}^{2}α$，$\sqrt{3}$sin2α）．
|AB|=$\sqrt{（sin2α-2\sqrt{3}co{s}^{2}α）^{2}+（2si{n}^{2}α-\sqrt{3}sin2α）^{2}}$=$\sqrt{8-8sin（2α-\frac{π}{6}）}$，
∵0≤α＜π，∴$-\frac{π}{6}$≤2α$-\frac{π}{6}$＜$\frac{11π}{6}$，∴$sin（2α-\frac{π}{6}）$∈[-1，1]．
∴|AB|=$\sqrt{8-8sin（2α-\frac{π}{6}）}$≤4，当$sin（2α-\frac{π}{6}）$=-1，即α=$\frac{5π}{6}$时取等号．
∴|AB|的最大值是4．
点评本题考查了极坐标方程化为直角坐标方程、直线的参数方程、两点之间的距离公式、圆的标准方程，考查了推理能力与计算能力，属于中档题．
