陕西省西安市长安区某校2024-2025学年第一学期八年级收心考试题(数学)

陕西省西安市长安区某校2024-2025学年第一学期八年级收心考试题(数学)试卷答案,我们目前收集并整理关于陕西省西安市长安区某校2024-2025学年第一学期八年级收心考试题(数学)得系列试题及其答案,更多试题答案请关注本网站↓↓↓

试题答案

陕西省西安市长安区某校2024-2025学年第一学期八年级收心考试题(数学)试卷答案

以下是该试卷的部分内容或者是答案亦或者啥也没有,更多试题答案请捕获只因

payingtribute(致敬)toFrance'srichhistory..21.WhatisspecialaboutDrottningholmPalace?A.Itisopentothepublic.B.Itisredecorated.C.It'stheresidenceofFrenchroyalfamily.D.It'saUNESCOWorldHeritageSite.22.WhatdotheattractionsofRoyalPalaceofMadridinclude?A.Thepaintinggallery.B.Ahistorymuseum.C.Beautifulstaterooms.D.Animpressivecastle.23.WhatcanwelearnaboutPalaceofVersailles?A.ThechangingoftheGuardceremony.B.TheprocessofFrenchRevolution.C.ThehistoryofSpanishroyals.D.Thewayoftheformerroyals'life.BGilliamwasborninTupelo,Mississippi,in1933astheseventhchildofeighttoafatherwhoworkedontherailroadandahomemakingmother.HeattendedtheUniversityofLouis-villeforbothbachelor'sandmaster'sdegrees,butin1962hemovedtoWashington,D.C.,wherehelivedandhadhisstudiofortherestofhislife.HebecameoneoftheleadingartistsoftheWashingtonColorSchool.Hewasveryinterestedinfreeinghispaintingsfromthelimitofcanvases(andframes.Instead,inhisDrapeworksofthe1960s,hetookunstretchedcanvasesandhungthemfromceilingsorpinned(themtowalls.Eachtimehiswork-partpainting,partsculpture-wasshowninanexhibition,ithungdifferently,neverthesamewaytwice.Ina2018MorningEditionprofile,GilliamexplainedthattheintentionbehindhisDrapeworkwas"todeveloptheideaofmovementintoshapes"-andthathewasinspiredbylaundry(洗衣店)hangingfromaclothesline.Hisworkisrepresentedinthecollectionsofsomeoftheworld'smostcelebratedmuse-ums,includingtheArtInstituteofChicago;theTateModerninLondon;andtheMuseed'ArtModerneinParis.In2015,hewasawardedStateDepartment'sMedalofArtsLifetimeAchievementAward.Inthe2018MorningEditionprofile,thethen84-year-oldGilliamsaidthathefeltthathewasinhisprime,despitehealthchallenges."I'veneverfeltbetterinmylife.Iliveforthisperiodofbeinginthestudioandactuallyworking."【高二英语第4页(共10页)】·23-151B·

分析由f′(x)≥k>0,可得f(x)在(0,+∞)递增,可令g(x)=f(x)-kx,求出导数,判断单调性,再由函数零点存在定理,即可得证.

解答证明:由f′(x)≥k>0,可得
f(x)在(0,+∞)递增,
可令g(x)=f(x)-kx,
由g′(x)=f′(x)-k≥0,
即有g(x)在(0,+∞)递增,
g(x)>g(0)=f(0),
则有f(x)-kx>f(0),
即f(x)>kx+f(0),
由f(0)<0,kx>0,当x→+∞,kx→+∞,
使得kx+f(0)>0,由f(x)在(0,+∞)递增,
根据函数零点存在定理,
可得f(x)在(0,+∞)内有且仅有一个零点.

点评本题考查导数的运用:求单调性,考查函数零点存在定理的运用,属于基础题.