广东省龙岗区2023-2024学年第一学期高一期末质量监测数学.考卷答案

广东省龙岗区2023-2024学年第一学期高一期末质量监测数学.考卷答案试卷答案,我们目前收集并整理关于广东省龙岗区2023-2024学年第一学期高一期末质量监测数学.考卷答案得系列试题及其答案,更多试题答案请关注微信公众号:考不凡/直接访问www.kaobufan.com(考不凡)

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广东省龙岗区2023-2024学年第一学期高一期末质量监测数学.考卷答案试卷答案

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教学札记Nooneremainsperfectlycalm,however.RonakPandit,theformerchampionshooter,saysthatwhenthereWhatisthepressure,thehandandfingerswillshake."Everyonefeelsthepressure,"saysPanditattheGamesVillage.PanditiA.HelpingdhooingwhichincludeshiswifeHecnaSidhu,thempistopCCheckingsaysthat,despitelifelongeffortstoslowdowntheheart,noonecanavoidtheshakingofthehandandthefingers.HeWhydoesBrkwiehappenedmrydingehake,hetththemA.Itonlywoneoterhrl10.1.ThheifferbechapC.Itisn'tsu11.Whyisemotiontheprimeenemyofshooting?WhatwouldA.Itcausesdiscomforttotheshooters.B.Itgoesasadistractionduringthesport.A.FishladdC.Itpreventspeoplefromlovingshooting.D.ItmakesthehandandfingershardtWhatcanbe12.WhatisthepurposeofBindra'sadrenalinetraining?A.HiscomA.Tostrengthenhismusclesforshooting.C.HethinkB.Togethisheartusedtoanextremesituation.与解析】C.Tohelpreducehispressurefromcompetition画因州的佩D.Togainunderstandingoflifefromexperienceofdanger修建鱼道对13.WhichofthefollowingstatementswillRonakPanditagreewith?B根据第2A.Championshooterssuffermuchlessshake.D根据第3B.Excellentshootersarebetteratdealingwithshake.华这个项目C.Well-trainedshooterscanfindwaystoavoidshaking.D.Itwilltakelifelongeffortstoavoidtheeffectofpressure.C命题视角】14.Whichofthefollowingisclosestinmeaningtotheunderlinedword"also-rans"?理解与分析A.Competitors.B.Experts.C.Losers.D.Supporters.[解题思路】【答案与解析】射击运动与一般的运动截然不同

一般的运动要求的是“动”,射击要求选手们“静”

这种管子,兴11.D根据第1段第5句可知,情绪的波动会影响血流的速度,从而使手和手指抖动

《C根据第12.B根据第2段末句可知,在这个训练中,他创造一种情形,在心跳加快的情形下使心脏尽量保持镇静

三部分完于13.B阅读下面乡【命题视角】本题考查学生依据语境对词意作出合理推测的能力

“Paulmus【解题思路】根据文章最后两句可知,RonakPandit认为在同样的抖动情况下,射击选手们的得分都不,样,这就是themup.选手之间的差别

由此推断,冠军选手更擅长克服抖动带来的影响

iswer.221l4.C根据画线词前面的championshooters可知,这里指未拿到冠军的选手,意为“落败者;落选者”

C项意思最接sPaul.近该画线词

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广东省龙岗区2023-2024学年第一学期高一期末质量监测数学.考卷答案

13.(2分)冬奥会冰壶比赛时,投手用力将冰壶掷出后,冰壶由于具有惯性,会继续沿着水平赛道向前滑行一段距离,它滑行时受到摩擦力(赛道的粗糙程度各处相同的作用在冰壶停止运动之前,冰壶受到的摩擦力(选填“逐渐减小”保持不或“逐渐增大”)=10&10×10.0