2024年2月海南省高三年级春季学期开学摸底联考数学.考卷答案

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2024年2月海南省高三年级春季学期开学摸底联考数学.考卷答案试卷答案

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扎记EYoumayfeellikeyoudon'thavetimetomakeadjustments.F.NeitherextremewillleadyoutoapleasantlifeforveryongG.However,reevalationandgrowthbringamorebeautifulfuture【答案15~19DCGFB第三部分语言知识运用(共两节,满分35分)getthe第一-节(共20小题:每小题1分,满分20分)阅读下面短文,从短文后各题所给的A,B,C和D四个选项中,选出可以填人空白处的最佳选项

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20.B我看着他从口袋里掏出皱巴巴的作业递给我

21D他回答道:“我的作业

”22.B我很震惊,因此我很长时间说不出话来

◇金太阳AB创新卷·英语(滚动卷)2022.11.1117:48

分析(Ⅰ)求出C到直线x-y+5=0的距离,根据直线x-y+5=0与圆C相交所得弦长为$2\sqrt{2}$,利用勾股定理,即可求半径r;
(Ⅱ)由$|PO|=\sqrt{2}|PA|$可得(x-4)2+y2=8,所以只需要圆C和圆(x-4)2+y2=8有公共点.

解答解:(Ⅰ)C到直线x-y+5=0的距离为d=$\frac{|1-4+5|}{\sqrt{2}}$=$\sqrt{2}$,直线与圆相交所得弦长为$2\sqrt{2}$,所以$r=\sqrt{2+2}=2$.
(Ⅱ)设P(x,y),由$|PO|=\sqrt{2}|PA|$可得(x-4)2+y2=8,
所以只需要圆C和圆(x-4)2+y2=8有公共点,两圆圆心距离为5,
所以$5-2\sqrt{2}≤r≤5+2\sqrt{2}$.

点评本题考查直线与圆、圆与圆的位置关系,考查学生的计算能力,属于中档题.