四川省2023-2024学年度上期高一年级高中2023级期中联考数学.考卷答案

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四川省2023-2024学年度上期高一年级高中2023级期中联考数学.考卷答案试卷答案

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选择性必修二UNIT2参考答案及部分解析参考答案1-5BCDBC6-10DDACB11.decided12.Comfortingly13.friends14.onupon15.points16.tochallenge17.making18.them19.where20.excellent21-25CBCDB26-30BCBCC31-34CBDC35-39FEGBD40.Itshowsthatourbrainneedsthecorrectfoodtoworkproperly.41.Thatpeoplecaneatparticularfoodforparticularmentalhealthissues.42.TheresearchbyJackaandSanchez-Villegas,whichhasbeenrecognizedbymanymedicalprofessionals,revealsthelinkbetweenthedietandmentalillnesses.Accordingtothefifthparagraph,manymedicalprofessionalsfeelthattheresultoftheresearchistooearly.Itneedsfurtherresearch.So,theresearchhasn'tbeenrecognizedbymanymedicalprofessionals.43.First,weshouldeatthreemealsregularly,especialbreakfast.Second,weshouldeatdifferentkindsoffood,suchasvegetables,milk,meat,fishandsoon.Third,weshouldavoidjunkfood.Forexample,snacksandcandies.Onepossibleversion:DearDavid,That'sreallygoodnews!ParticipatinginthisprogrammewillbeagoodwaytoexperienceChineseculture.Furthermore,youwillbeabletomakenewfriendsinthisexcitingjourneyoflife.Lastbutnotleast,comparedwithmanyWesterncountries,it'scheapertolive,eatandtravelinChina.There'snodenyingyoumayhavedifficulties,forexample,overcomingcultureshock,learninganewlanguageandmaintaininglong-distancefriendships.ButIbelieveChinesepeople'skindnessandfriendlinesswillmakeyouradaptationeasier.Inshort,Istronglyrecommendsigningupforthisprogramme.Yours,LiHua部分解析阅读理解第一节A篇主题语境:人与社会一一社会服务本文是应用文

文章是对一个志愿者故事项目的介绍

2I.C

理解具体信息

根据第一个故事中的AsthefounderandleaderoftheFaithFoodBank.tomakesurepeoplegetfed可知,Roxana在努力解决她所在社区的粮食问题

22.B

理解具体信息

根据第二个故事中的Youcanfindthesevolunteersremodelingfacilities.forlow-incomedisabledindividualsandseniors可知,Cindy和Larry的工作包括提供各式各样的志愿者服务

分析根据向量共线的充要条件,可得存在实数λ,使$\overrightarrow{a}=λ\overrightarrow{b}$,即$\left\{\begin{array}{l}m+1=6λ\\0=(2n-1)λ\\2m=2λ\end{array}\right.$,解得答案.

解答解:∵$\overrightarrow{a}=(m+1,0,2m),\overrightarrow{b}=(6,2n-1,2),\overrightarrow{a}∥\overrightarrow{b}$,
∴存在实数λ,使$\overrightarrow{a}=λ\overrightarrow{b}$,
即$\left\{\begin{array}{l}m+1=6λ\\0=(2n-1)λ\\2m=2λ\end{array}\right.$,
解得:m=λ=$\frac{1}{5}$,n=$\frac{1}{2}$,
故选:A

点评本题考查的知识点是共线向量,熟练掌握共线向量的充要条件,是解答的关键.