2024届湖北省宜荆荆五月高考适应性考试数学.考卷答案试卷答案,我们目前收集并整理关于2024届湖北省宜荆荆五月高考适应性考试数学.考卷答案得系列试题及其答案，更多试题答案请关注本网站↓↓↓
2024届湖北省宜荆荆五月高考适应性考试数学.考卷答案试卷答案
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分析（1）因为函数f（x）=sin（2x+φ）在对称轴时有最大或最小值，据此就可得到含φ的等式，求出φ值．
（2）借助基本正弦函数的单调性来解可．
（3）利用五点法作图，可得到函数在区间[0，π]上的点的坐标，再把坐标表示到直角坐标系，用平滑的曲线连接即可得到所求图象．
解答解：（1）因x=$\frac{π}{3}$是函数y=f（x）的图象的对称轴，所以sin（$\frac{2π}{3}$+φ）=±1
即$\frac{2π}{3}$+φ=kπ+$\frac{π}{2}$，k∈Z．
因为-π＜φ＜0，所以φ=-$\frac{π}{6}$．
（2）由（1）知f（x）=sin（2x-$\frac{π}{6}$）．
由题意得2kπ+$\frac{π}{2}$≤2x-$\frac{π}{6}$≤2kπ+$\frac{3π}{2}$，k∈Z，
所以函数f（x）=sin（2x-$\frac{π}{6}$）的单调减区间为[kπ+$\frac{π}{3}$，kπ+$\frac{5π}{6}$]，k∈Z．
（3）由f（x）=sin（2x-$\frac{π}{6}$）知：
点评本小题主要考查根据三角函数的性质求解析式，以及单调区间，三角函数图象的画法，考查学生的推理和运算能力．
