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安徽2024-2025学年九年级开学考试题(数学)试卷答案
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payingtribute(致敬)toFrance'srichhistory..21.WhatisspecialaboutDrottningholmPalace?A.Itisopentothepublic.B.Itisredecorated.C.It'stheresidenceofFrenchroyalfamily.D.It'saUNESCOWorldHeritageSite.22.WhatdotheattractionsofRoyalPalaceofMadridinclude?A.Thepaintinggallery.B.Ahistorymuseum.C.Beautifulstaterooms.D.Animpressivecastle.23.WhatcanwelearnaboutPalaceofVersailles?A.ThechangingoftheGuardceremony.B.TheprocessofFrenchRevolution.C.ThehistoryofSpanishroyals.D.Thewayoftheformerroyals'life.BGilliamwasborninTupelo,Mississippi,in1933astheseventhchildofeighttoafatherwhoworkedontherailroadandahomemakingmother.HeattendedtheUniversityofLouis-villeforbothbachelor'sandmaster'sdegrees,butin1962hemovedtoWashington,D.C.,wherehelivedandhadhisstudiofortherestofhislife.HebecameoneoftheleadingartistsoftheWashingtonColorSchool.Hewasveryinterestedinfreeinghispaintingsfromthelimitofcanvases(andframes.Instead,inhisDrapeworksofthe1960s,hetookunstretchedcanvasesandhungthemfromceilingsorpinned(themtowalls.Eachtimehiswork-partpainting,partsculpture-wasshowninanexhibition,ithungdifferently,neverthesamewaytwice.Ina2018MorningEditionprofile,GilliamexplainedthattheintentionbehindhisDrapeworkwas"todeveloptheideaofmovementintoshapes"-andthathewasinspiredbylaundry(洗衣店)hangingfromaclothesline.Hisworkisrepresentedinthecollectionsofsomeoftheworld'smostcelebratedmuse-ums,includingtheArtInstituteofChicago;theTateModerninLondon;andtheMuseed'ArtModerneinParis.In2015,hewasawardedStateDepartment'sMedalofArtsLifetimeAchievementAward.Inthe2018MorningEditionprofile,thethen84-year-oldGilliamsaidthathefeltthathewasinhisprime,despitehealthchallenges."I'veneverfeltbetterinmylife.Iliveforthisperiodofbeinginthestudioandactuallyworking."【高二英语第4页（共10页）】·23-151B·
分析（1）利用${C}_{n}^{m}={C}_{n}^{n-m}$和${C}_{n}^{m}+{C}_{n}^{m+1}={C}_{n+1}^{m+1}$，能求出结果．
（2）利用${C}_{n}^{m}+{C}_{n}^{m+1}={C}_{n+1}^{m+1}$，能得到C${\;}_{2}^{2}$+C${\;}_{3}^{2}$+C${\;}_{4}^{2}$+…+C${\;}_{10}^{2}$=${C}_{11}^{3}$，由此能求出结果．
解答解：（1）（C${\;}_{100}^{98}$+C${\;}_{100}^{97}$）÷A${\;}_{101}^{3}$
=（${C}_{100}^{2}+{C}_{100}^{3}$）÷${A}_{101}^{3}$
=${C}_{101}^{3}÷{A}_{101}^{3}$
=$\frac{1}{3！}$
=$\frac{1}{6}$．
（2）C${\;}_{2}^{2}$+C${\;}_{3}^{2}$+C${\;}_{4}^{2}$+…+C${\;}_{10}^{2}$
=${C}_{4}^{3}+{C}_{4}^{2}+{C}_{5}^{2}+…+{C}_{10}^{2}$
=${C}_{5}^{3}+{C}_{5}^{2}+{C}_{6}^{2}+…+{C}_{10}^{2}$
=${C}_{6}^{3}+{C}_{6}^{2}+{C}_{7}^{2}+…+{C}_{10}^{2}$
=${C}_{7}^{3}+{C}_{7}^{2}+{C}_{8}^{2}+…+{C}_{10}^{2}$
=${C}_{8}^{3}+{{C}_{8}^{2}+C}_{9}^{2}+{C}_{10}^{2}$
=${C}_{9}^{3}+{C}_{9}^{2}+{C}_{10}^{2}$
=${C}_{10}^{3}+{C}_{10}^{2}$
=${C}_{11}^{3}$
=$\frac{11×10×9}{3×2×1}$
=165．
点评本题考查组合数公式化简求值，是基础题，解题时要认真审题，注意组合数公式的性质的合理运用．
